The total 和 expands as Q+2R Q+2R Q+2R.
译文:By Q+2R=(∑ixi)2 Q+2R=\left(\sum_i x_i\right)^2Q+2R=(∑ixi)2 且 Q,2R≥0 Q,2R\ge0Q,2R≥0 译文:, AM–GM gives (Q+2R)2≥4Q(2R)=8QR(Q+2R)^2\ge4Q(2R)=8QR (Q+2R)2≥4Q(2R)=8QR. 所以 left side 是在most (∑ixi)4/8(\sum_i x_i)^4/8(∑ixi)4/8.