MathLabs

第3题

Twenty-one girls 且twenty-one boys took part 中a mathematical contest. Each contestant solved 在most six problems. F或每个girl 且每个boy, 在least one problem was solved 由both 的them. 证明 there was a problem solved 由在least three girls 且在least three boys.
第 1/5 步:假设 contrary
通俗地说

No problem has three solvers 的每个sex.

∣Gp∣≤2or∣Bp∣≤2|G_p|\le2\quad\text{or}\quad|B_p|\le2
详细分析

F或每个problem p p 译文:, let Gp,Bp G_p,B_p be its girl 且boy solver sets. 假设 ∣Gp∣≤2|G_p|\le2 或 ∣Bp∣≤2|B_p|\le2 对每个 p p .