Eliminate highest-degree terms.
设 D=ab2+b+7 D=ab^2+b+7D=ab2+b+7 且 E=a2b+a+b E=a^2b+a+b E=a2b+a+b 译文:. Since aD−bE=7a−b2 aD-bE=7a-b^2aD−bE=7a−b2 译文:, we have D∣7a−b2 D\mid 7a-b^2D∣7a−b2.